# Physics

A home run is hit such a way that the baseball just clears a wall 26 m high located 114 m from home plate. The ball is hit at an angle of 35â—¦ to the horizontal, and air resistance is negligible. Assume the ball is hit at a height of 2 m above the ground.

What is the initial speed of the ball? The acceleration of gravity is 9.8 m/s2 .

How much time does it take for the ball to reach the wall?

Find the speed of the ball when it reaches the wall.

1. 0
2. 1
1. 35 degrees*

1. 0
posted by Sam
2. a. Range = Vo^2*sin(2A)/g.
114 = Vo^2*sin(70)/9.8,
Vo = 34.5 m/s.

b. Xo = Vo*cos35 = 34.5*cos35 = 28.2 m/s. = Hor. component.
Yo = 34.5*sin35 = 19.8 m/s = Ver. component.

Y = Yo + g*Tr.
0 = 19.8 -9.8Tr,
Tr = 2.02s. = Rise time. = Time to reach the wall.

h = ho + Yo*Tr + 0.5g*Tr^2.
h = 2 + 19.8*2.02 - 4.9*2.02^2 = 22m above gnd. = max ht.
If the max. ht. is 22 m, the wall can't
be 26 m high. Check the given ht.

c. Assuming the ball is at max. ht. when it reaches the wall:
V = Xo + Yi = 28.2 + 0i = 28.2 m/s.

1. 0
posted by Henry

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