In the following reaction, first find how many oxygen molecules would be used to completely react with 230 grams of pentyl alcohol (C5H11OH)? Then, if exactly 1.505x10^21 carbon dioxide molecules were formed in this reaction, calculate the grams of water formed during this reaction. C5H11OH+O2 ---->CO2+H2O
See the response by Steve above.
To answer the first part of the question, we need to calculate the number of moles of pentyl alcohol (C5H11OH) in 230 grams.
To do this, we need to know the molar mass of pentyl alcohol. Let's calculate it:
C: 5 carbon atoms in one molecule of C5H11OH, so 5 * atomic mass of carbon = 5 * 12.01 g/mol
H: 11 hydrogen atoms in one molecule of C5H11OH, so 11 * atomic mass of hydrogen = 11 * 1.008 g/mol
O: 1 oxygen atom in one molecule of C5H11OH, so 1 * atomic mass of oxygen = 1 * 16.00 g/mol
Now, add up the molar masses:
5 * 12.01 g/mol + 11 * 1.008 g/mol + 1 * 16.00 g/mol = 88.15 g/mol
Now we can calculate the number of moles of pentyl alcohol:
moles of pentyl alcohol = mass of pentyl alcohol / molar mass of pentyl alcohol
moles of pentyl alcohol = 230 g / 88.15 g/mol
Calculate this value to find the number of moles of pentyl alcohol.
To determine the number of oxygen molecules needed for the reaction, we need to refer to the balanced chemical equation:
C5H11OH + O2 → CO2 + H2O
From the equation, we can see that the stoichiometric ratio between C5H11OH and O2 is 1:1. This means that for every 1 mole of pentyl alcohol, we need 1 mole of oxygen.
So the number of oxygen molecules required is equal to the number of moles of pentyl alcohol.
Now, to calculate the grams of water formed during this reaction, we need to use the number of carbon dioxide (CO2) molecules formed.
From the balanced chemical equation, we can determine that the stoichiometric ratio between CO2 and H2O is 1:1. This means that for every 1 mole of carbon dioxide formed, we also have 1 mole of water produced.
Therefore, the grams of water formed can be calculated by converting the number of carbon dioxide molecules to moles of CO2 and then to grams of water using the molar mass of water (H2O).
First, determine the number of moles of CO2:
moles of CO2 = number of CO2 molecules / Avogadro's number
Then, convert moles of CO2 to grams of water:
grams of water = moles of CO2 * molar mass of water
Using these steps, you can calculate the grams of water formed during the reaction if exactly 1.505x10^21 carbon dioxide molecules were formed.