Review the information.
In Compound A, Element W has an electronegativity of 2.8, and Element X has an electronegativity of 2.5.
In Compound B, Element Y has an electronegativity of 2.0, and Element Z has an electronegativity of 3.8.
Which statement correctly identifies the ionic compound and describes the use of electronegativity in determining this?
A. Compound A is ionic. The electronegativity difference is 5.3, which can be determined by adding the electronegativity of Element W to Element X. Electronegativity differences greater than 1.7 indicate ionic bonds.
B. Compound B is ionic. The electronegativity difference is 1.8, which can be determined by subtracting the electronegativity of Element Y from Element Z. Electronegativity differences greater than 1.7 indicate ionic bonds.
C. Compound A is ionic. The electronegativity difference is 0.3, which can be determined by subtracting the electronegativity of Element X from Element W. Electronegativity differences less than 1.7 indicate ionic bonds.
D. Compound B is ionic. The electronegativity difference is 5.8, which can be determined by adding the electronegativity of Element Y to Element Z. Electronegativity differences greater than 1.7 indicate ionic bonds.
I think it is B
yes
Thank you
You are correct. The statement "Compound B is ionic. The electronegativity difference is 1.8, which can be determined by subtracting the electronegativity of Element Y from Element Z. Electronegativity differences greater than 1.7 indicate ionic bonds" is the correct answer. This statement correctly identifies the ionic compound and describes the use of electronegativity in determining this. In general, when the electronegativity difference between two elements is greater than 1.7, it indicates the presence of an ionic bond.
To determine the correct answer, we need to understand how electronegativity is used to identify ionic compounds.
Electronegativity is a measure of an atom's ability to attract electrons in a chemical bond. In general, when two atoms with significantly different electronegativities bond, the bond will be polar. If the electronegativity difference is large enough, the bond will be considered ionic.
Now let's analyze the information given:
In Compound A, Element W has an electronegativity of 2.8, and Element X has an electronegativity of 2.5. The electronegativity difference here is 2.8 - 2.5 = 0.3.
In Compound B, Element Y has an electronegativity of 2.0, and Element Z has an electronegativity of 3.8. The electronegativity difference here is 3.8 - 2.0 = 1.8.
According to the information provided, the electronegativity difference in Compound A is 0.3, while in Compound B, it is 1.8.
Now let's evaluate the answer choices:
A. Compound A is ionic. The electronegativity difference is 5.3, which can be determined by adding the electronegativity of Element W to Element X. Electronegativity differences greater than 1.7 indicate ionic bonds.
- This statement is incorrect because it describes an electronegativity difference of 5.3 for Compound A, which is not consistent with the given information.
B. Compound B is ionic. The electronegativity difference is 1.8, which can be determined by subtracting the electronegativity of Element Y from Element Z. Electronegativity differences greater than 1.7 indicate ionic bonds.
- This statement correctly identifies Compound B as ionic, as the electronegativity difference is 1.8 which is greater than the threshold of 1.7. It is consistent with the given information.
C. Compound A is ionic. The electronegativity difference is 0.3, which can be determined by subtracting the electronegativity of Element X from Element W. Electronegativity differences less than 1.7 indicate ionic bonds.
- This statement is incorrect because it describes the electronegativity difference of 0.3 for Compound A, which is not consistent with the given information.
D. Compound B is ionic. The electronegativity difference is 5.8, which can be determined by adding the electronegativity of Element Y to Element Z. Electronegativity differences greater than 1.7 indicate ionic bonds.
- This statement is incorrect because it describes an electronegativity difference of 5.8 for Compound B, which is not consistent with the given information.
Therefore, the correct answer is B. Compound B is ionic, as the electronegativity difference between Element Y and Element Z is 1.8, which exceeds the threshold of 1.7.