A jar contains 36 marbles if has 20 red 12 black and 4 green marbles two marbles are draw the first is not returned before the second one is drawn what is the probability that both marbles are red
prob(red, red) = (20/36)(19/35) = ....
To find the probability that both marbles drawn are red, we need to determine the total number of possible outcomes and the number of favorable outcomes.
Total number of marbles in the jar = 36 (20 red + 12 black + 4 green)
When the first marble is drawn, there are now 35 marbles remaining in the jar. However, since the first marble is not returned before the second marble is drawn, the total number of marbles decreases to 34 for the second draw.
Number of favorable outcomes:
Since the first marble drawn is not returned, we have 20 red marbles remaining in the jar for the second draw.
Number of possible outcomes:
Since the first marble drawn is not returned, there are now 34 marbles remaining in the jar for the second draw.
Therefore, the probability that both marbles drawn are red can be calculated as:
P(both red) = (Number of favorable outcomes) / (Number of possible outcomes)
= (20/34) * (20/35)
≈ 0.3333 * 0.5714
≈ 0.1905 or 19.05%
So, the probability that both marbles drawn are red is approximately 0.1905 or 19.05%.