d+s ˃ -3
d ˃ -7
find s
it says the answer is 4 (s=4) but it seems not ok because depending on d the number can be pretty much anything
subtract them, (valid since both inequality signs are the same)
d+s - d > -3 - (-7)
s > 4
I don't like that subtraction. Subtracting a larger value gives a smaller result. For example, suppose we have small x > 0
d = -7+x > -7
d+s = -7+x+s > -3
x+s > 4
s > 4-x
So, suppose x = .1, and thus
d = -7+.1 = -6.9
If s > 4-.1 = 3.9, ok, since d+s > -3
If s = 3.99, d+s = -6.9+3.99 = -2.91
So, we don't have to have s>4, as long as it's closer to 4 than d is to -7.
let d = -6.9, valid for d > -7
-6.9+s > -3
s > 3.9 which is NOT s > 4
Yup, Steve is right, we have one exception which rules out my entire solution.
To find the value of "s" given the inequalities d + s > -3 and d > -7, we need to consider the values that satisfy both conditions.
First, let's simplify the inequality d + s > -3 by isolating "s":
d + s > -3
s > -3 - d (subtracting d from both sides)
Now, we can substitute the second inequality d > -7 into the inequality above:
s > -3 - (-7)
s > -3 + 7
s > 4
From this inequality, we can see that "s" must be greater than 4 in order to satisfy the conditions. However, since there is no further information or constraints provided, "s" can take any value greater than 4, such as 5, 6, 7, and so on.
Therefore, it is not accurate to say that the answer is specifically "s = 4". The solution set for "s" is an open interval ranging from 4 onwards.