Twice a number added to half of itself equal 20. Find the number
Let assume number = x
2x + x/2 = 20
4x + x = 40
5x = 40
X = 8
2x+x/2=20
3x/2=20
3x=20×2
3x=40
X=40/3
Twice a number added to half of equals 20 find the number
Dash
let the number we dont know = x
2x+x/2=20
now multply 2 from both sides
2(2x)+x=2(20)
4x+x=40
now add 4x to x
5x=40
now divide both sides from 5 to eliminate coifficient
5x/5=40/5
now we get 8 as an answer
x+8
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Let assume number = x
2x + x/2 = 20
now multply 2 from both sides
2(2x+x/2)=2(20)
4x+2x/2=40
4x + x = 40
5x = 40
X = 8
To find the number, we can set up an equation based on the given information. Let's call the number "x".
According to the given information, "Twice a number added to half of itself equal 20". Mathematically, we can express this as:
2x + (1/2)x = 20
Now, we need to solve this equation to find the value of x.
To do that, we can simplify the equation by combining like terms:
(2 + 1/2)x = 20
To remove the fraction, we can multiply both sides of the equation by the denominator of the fraction, 2:
(2 + 1/2)x * 2 = 20 * 2
Simplifying further:
(5/2)x = 40
Now, we can isolate x by dividing both sides of the equation by 5/2:
x = 40 / (5/2)
To divide by a fraction, we can multiply by its reciprocal:
x = 40 * (2/5)
Simplifying the product:
x = 16
Therefore, the number is 16.