An urn contains 10 red balls, 6 green balls, 15 orange balls, and 14 blue balls.
If one ball is randomly drawn from the urn, what are the odds against the ball being red?
State your answer as a ratio using a colon to separate the two numbers.
35:45 = 7:9
prob(red) = 10/45 = 2/9
so , prob(not red) = 7/9
odds against red ball
prob(not red) : prob(red)
= (7/9) : (2/9)
= 7 : 2
Well, let's do some counting, shall we? There are a total of 45 balls in the urn, and out of those, 10 are red. So, the odds against drawing a red ball would be the number of non-red balls divided by the number of red balls.
The number of non-red balls is 6 (green) + 15 (orange) + 14 (blue), which gives us 35.
Therefore, the odds against drawing a red ball would be 35:10 or simplified, 7:2.
In other words, for every 7 non-red balls, there are 2 red balls. So, the odds are clownishly against drawing a red ball!
To find the odds against the ball being red, we need to determine the number of non-red balls in the urn.
There are a total of 10 red balls, and the urn contains a total of 10 + 6 + 15 + 14 = 45 balls.
The number of non-red balls is therefore 45 - 10 = 35.
The odds against the ball being red can be expressed as a ratio of the number of non-red balls to the number of red balls.
Therefore, the odds against the ball being red are 35:10.
To find the odds against the ball being red, we first need to determine the total number of balls in the urn. The urn contains 10 red balls, 6 green balls, 15 orange balls, and 14 blue balls, totaling 10 + 6 + 15 + 14 = 45 balls.
Next, we need to determine the number of balls that are not red. In this case, it would be the sum of the green, orange, and blue balls, which is 6 + 15 + 14 = 35 balls.
Finally, we can express the odds against the ball being red as a ratio using a colon. The odds against the ball being red are 35:10.