48% of the students in the school are female and the probability of taking of physics is independent of the gender of the student, what is the probability that a student chosen at random is both a female and taking physics?

Note: If A and B are independent events, P(A and B) = P(A)*P(B)

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P(female and physics) = P(female)*P(physics) = 0.48*P(physics)
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Cheers,
Stan H.
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To find the probability that a student chosen at random is both a female and taking physics, we need to multiply the probability of being female by the probability of taking physics.

Let's assume there are 100 students in total for simplicity. If 48% of the students are female, then there are 48 female students and 52 male students.

Since the probability of taking physics is independent of gender, it remains constant for both male and female students. Let's represent this probability by P(Physics).

Since we have 48 female students, the probability that a student chosen at random is female is 48/100 = 0.48.

Therefore, the probability of a female student taking physics is P(Female) * P(Physics) = 0.48 * P(Physics).

Note that we don't know the value of P(Physics), so we cannot calculate the exact probability without this information.