the elevation at which a baseball game is played affects the distance a ball travels when hit. For every increase of 1,000 ft. in elevation, the ball travels about 6 feet farther. Suppose Frank hits a ball that travels 220 ft. when hit in a ballpark at sea level. write an function for the distance the ball travels as a function of the elevation of the ball park. How far would the same ball travel if it were hit in a park with an elevation of 2,500 ft.?

Question

the elevation at which a baseball game is played affects the distance a ball travels when hit. For every increase of 1,000 ft. in elevation, the ball travels about 6 feet farther. Suppose Frank hits a ball that travels 220 ft. when hit in a ballpark at sea level. write an function for the distance the ball travels as a function of the elevation of the ball park. How far would the same ball travel if it were hit in a park with an elevation of 2,500 ft.?

Answer 1

D = Do + (h/1000)*6ft

D = 220 + (2500/1000)6ft = 235 ft.

Answer 2

To write a function for the distance the ball travels as a function of the elevation, we can use the given information that for every increase of 1,000 ft in elevation, the ball travels about 6 feet farther. Let's denote the elevation in feet as "e" and the distance the ball travels as "d".

We can use the equation:
d = 220 + 6 * (e / 1000)

Substituting the elevation of 2,500 ft, we can find out how far the ball would travel in that park.

d = 220 + 6 * (2500 / 1000)
d = 220 + 6 * 2.5
d = 220 + 15
d = 235 feet

Therefore, if the ball were hit in a park with an elevation of 2,500 ft, it would travel approximately 235 feet.

Answer 3

To write a function for the distance the ball travels as a function of the elevation of the ballpark, we need to consider the relationship between elevation and the distance the ball travels.

According to the given information, for every increase of 1,000 ft. in elevation, the ball travels about 6 feet farther. So, we can establish the following relationship:

Distance at Sea Level + (Increase in elevation in 1,000 ft. increments) * (6 ft.)

Let's call the distance at sea level D0 and the elevation of the ballpark E.

The function for the distance the ball travels as a function of the elevation of the ballpark can be written as:

Distance = D0 + (E - 0) * (6 ft.)

Now let's calculate how far the ball would travel if it were hit in a park with an elevation of 2,500 ft.

Distance = D0 + (2,500 ft. - 0) * (6 ft.)

Substituting the given values:

Distance = 220 ft. + (2,500 ft.) * (6 ft.)

Calculating the result:

Distance = 220 ft. + 15,000 ft.

Distance = 15,220 ft.

Therefore, if the ball were hit in a park with an elevation of 2,500 ft., the ball would travel approximately 15,220 ft.