How many grams of N2F4 can be produced from 361 g F2?
molar mass of F = 19
so F2 is 38 grams/mol
so we have 361/38 mols of F2
we get half as many mols of N2F4
so 361/76 mols of N2F4
molar mass of N2F4 = 28 + 76 = 104 grams/mol
so
104 * 361 / 76 grams
To answer this question, we first need to determine the balanced chemical equation for the reaction between F2 and N2F4.
The balanced chemical equation is:
N2 + 3F2 -> 2N2F4
This equation tells us that 1 mole of N2 reacts with 3 moles of F2 to produce 2 moles of N2F4.
Step 1: Convert grams of F2 to moles of F2.
To do this, we need to know the molar mass of F2. The molar mass of F2 is 38.00 g/mol.
moles of F2 = mass of F2 / molar mass of F2
= 361 g / 38.00 g/mol
= 9.50 moles of F2
Step 2: Use the mole ratio from the balanced chemical equation to determine the moles of N2F4 produced.
From the balanced chemical equation, we know that 3 moles of F2 react with 2 moles of N2F4.
moles of N2F4 = (moles of F2 / 3) * (2 moles of N2F4 / 3 moles of F2)
= (9.50 / 3) * (2 / 3)
= 3.17 moles of N2F4
Step 3: Convert moles of N2F4 to grams of N2F4.
To do this, we need to know the molar mass of N2F4. The molar mass of N2F4 is 104.00 g/mol.
mass of N2F4 = moles of N2F4 * molar mass of N2F4
= 3.17 moles * 104.00 g/mol
= 329.68 g
Therefore, from 361 g F2, you can produce approximately 329.68 grams of N2F4.
To determine the grams of N2F4 that can be produced from 361 g F2, we need to balance the chemical equation for the reaction between F2 and N2F4.
The balanced equation for the reaction is:
3 F2 + N2 -> 2 N2F4
From the balanced equation, we can see that 3 moles of F2 react with 1 mole of N2F4 to produce 2 moles of N2F4.
To calculate the number of moles of F2, we use the formula:
moles = mass / molar mass
The molar mass of F2 is 38.0 g/mol.
moles of F2 = 361 g / 38.0 g/mol ≈ 9.5 mol
Using the mole ratio from the balanced equation, we can determine the moles of N2F4 that can be produced:
moles of N2F4 = (2 moles N2F4 / 3 moles F2) * 9.5 moles F2 ≈ 6.3 mol
Finally, we can calculate the grams of N2F4 produced using the molar mass of N2F4:
grams of N2F4 = moles of N2F4 * molar mass of N2F4
The molar mass of N2F4 is 104.0 g/mol.
grams of N2F4 = 6.3 mol * 104.0 g/mol ≈ 655 g
Therefore, approximately 655 grams of N2F4 can be produced from 361 grams of F2.