A car starts from rest and accelerates uniformly at 2m/s2 for 10 sec . Find the velocity and displacement at the end of 10 seconds .
v = a t = 2*10
d = (1/2) a t^2 = 10^2
To find the velocity and displacement at the end of 10 seconds, we can use the equations of motion.
First, let's find the velocity. We can use the equation:
v = u + at
where:
v = final velocity
u = initial velocity (in this case, the car starts from rest, so u = 0)
a = acceleration (2 m/s^2)
t = time (10 seconds)
Plugging in the values, we can find:
v = 0 + 2 * 10
= 20 m/s
So, at the end of 10 seconds, the velocity of the car is 20 m/s.
Now, let's find the displacement. We can use the equation:
s = ut + (1/2)at^2
where:
s = displacement
u = initial velocity (0 m/s)
a = acceleration (2 m/s^2)
t = time (10 seconds)
Plugging in the values, we can find:
s = 0 * 10 + (1/2) * 2 * (10)^2
= 0 + 1 * 2 * 100
= 0 + 200
= 200 meters
So, at the end of 10 seconds, the displacement of the car is 200 meters.