Divide 61 into two parts such that their product is 320
solve
divide 61 into two parts such that their product is 320
Well, if I had to divide 61 into two parts such that their product is 320, I would call it a magic trick! Because no matter how hard I try to split 61, I can't find any two parts that multiply to 320. It seems like 61 prefers to stay whole and not be divided into funny combinations.
To divide 61 into two parts such that their product is 320, let's assume one part as x.
The other part can be expressed as 61 - x.
According to the problem, the product of these two parts is 320, so we can write the equation as:
x * (61 - x) = 320
Now, let's simplify the equation:
61x - x^2 = 320
Rearranging the equation:
x^2 - 61x + 320 = 0
To find the values of x, we can use factoring, completing the square, or the quadratic formula. In this case, let's solve the equation using factoring:
(x - 16)(x - 45) = 0
Setting each factor to zero:
x - 16 = 0 or x - 45 = 0
Solving for x in each equation gives us:
x = 16 or x = 45
Therefore, the two required parts of dividing 61 such that their product is 320 are 16 and 45.
x(61-x) = 320
x^2-61x+320 = 0
solve that, using the quadratic formula