You have a solution of 0.500 M NaCl. If you add an equal amount of water to this solution, doubling the volume, what is the concentration of this solution?

same number of mols of NaCL

so half as many per liter
0.250 M

Thank you!

You are welcome :)

Well, you see, when you add an equal amount of water to the solution, you're not really changing the amount of NaCl in there, just the volume. So, the concentration of the solution would be halved, just like that time I told a chemistry joke and no one reacted. It was a real dilution!

To find the concentration of the solution after adding an equal amount of water, you can use the dilution equation:

Concentration1 x Volume1 = Concentration2 x Volume2

Let's break down the given information:

Concentration1 = 0.500 M (initial concentration of the NaCl solution)
Volume1 = V (initial volume of the NaCl solution)

After adding an equal amount of water, the volume doubles. So:

Volume2 = 2V (final volume of the solution)

Since the concentration refers to the amount of solute (NaCl) in a given volume of solvent (water), and we didn't add any more solute, the concentration of NaCl in the solution remains the same (Concentration2 = 0.500 M).

Now, we can substitute these values into the dilution equation:

0.500 M x V = 0.500 M x (2V)

Simplifying the equation:

0.500 V = 1.000 V

Dividing both sides of the equation by V:

0.500 = 1.000

Therefore, the concentration of the solution after adding an equal amount of water is still 0.500 M.