What is the outlier for the following set 0,0,1,2,4,5,5,5,5,5,5,5,5,5,5,5,5,6,6,7,7,7,7,8,9
And why
5. Your looking with the number with the most of the same number.
You are describing what the mode is. I asked for the outlier
oops I apologize. :o
I don't think this group of numbers has an outlier.
https://www.mathsisfun.com/definitions/outlier.html
Thanks, that what we thought too.
You're welcome.
To find the outlier in a set of numbers, we need to determine the value that is significantly different from the other values in the set.
To start, we can organize the set of numbers in ascending order: 0, 0, 1, 2, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 7, 7, 7, 7, 8, 9.
To identify the outlier, we can use a numerical method called the "1.5 times the interquartile range (IQR)" rule.
Step 1: Find the first quartile (Q1) and the third quartile (Q3) of the data set.
Q1 is the median of the lower half of the values, and Q3 is the median of the upper half.
In our example, Q1 = 4 and Q3 = 7.
Step 2: Calculate the IQR by subtracting Q1 from Q3.
IQR = Q3 - Q1 = 7 - 4 = 3.
Step 3: Apply the 1.5 times the IQR rule.
Multiply the IQR by 1.5: 3 * 1.5 = 4.5.
Step 4: Identify any values that are more than 1.5 times the IQR above Q3 or below Q1.
In our example, Q3 + 1.5 * IQR = 7 + 4.5 = 11.5.
The value 9 is the only value less than 11.5, so it is the only potential outlier.
However, to be absolutely sure that 9 is an outlier, we can also check if there are any values more than 1.5 times the IQR below Q1.
Q1 - 1.5 * IQR = 4 - 4.5 = -0.5.
There are no values less than -0.5 in the given data set.
Based on the calculations, the value 9 is the outlier in the given set.