
I don't see your choices, so how can we check?

My answers
2.D
3.also D
4.A

clearly not 2D. Just plug in y=2
2+4 = 6 = 6 Bzzzt
#3 is also wrong. You forgot to divide by 2.
2r = 12, not r = 12
#4 is correct

The last one is correct, the first two are wrong.
Show me your steps so I can tell where you are going wrong.


Just number 2 I'm not even understanding where to start

#2 is the main one i need help with

Why are you ignoring Reiny's advice?

I said i don't even know where to start with it

#2
 y+4 <1
Use your definition:
y+4 < 1 AND y4 < 1
y < 3 AND y < 5
y < 3 AND y > 5
or as they wrote it, 5 < y < 3


#2. Remember that
x = x if x >= 0
x = x if x < 0
So, you have
y+4 < 1
so, either y+4 >= 0, meaning y >= 4
or y+4 < 0, meaning y < 4
If y >= 4
y+4 < 1
y < 3
If y < 4
(y+4) < 1
y4 < 1
5 < y
But also, we started with y < 4
So the solution is 5 < y < 3
Or, think of what y+4 means. If y = 4, then y+4=0. So, y+4 is the distance from y to 4. If that distance is less than 1, then you see the solution. Plot the value 4 on the number line. y must be less than 1 unit away from 4.