For 1 mole of each of the following, how many moles of ions are present when they are dissolved in water?
(NH4)2CO3
NaBr
Mg(ClO4)2
HCl
I don't understand why you having a hard time understanding the question if its that easy why don't your explain it. DrBob222
To determine how many moles of ions are present when these compounds are dissolved in water, we need to consider the dissociation of the compounds into their respective ions.
(NH4)2CO3:
When (NH4)2CO3 is dissolved in water, it dissociates into 2 NH4+ ions and 1 CO3^2- ion. Therefore, there are a total of 3 moles of ions present.
NaBr:
When NaBr is dissolved in water, it dissociates into 1 Na+ ion and 1 Br- ion. Therefore, there are a total of 2 moles of ions present.
Mg(ClO4)2:
When Mg(ClO4)2 is dissolved in water, it dissociates into 1 Mg^2+ ion and 2 ClO4^- ions. Therefore, there are a total of 3 moles of ions present.
HCl:
When HCl is dissolved in water, it dissociates into 1 H+ ion and 1 Cl- ion. Therefore, there are a total of 2 moles of ions present.
So, the number of moles of ions present when each of these compounds is dissolved in water are as follows:
(NH4)2CO3: 3 moles of ions
NaBr: 2 moles of ions
Mg(ClO4)2: 3 moles of ions
HCl: 2 moles of ions.