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A 50 gram bullet moving with a velocity 10 m/s gets embedded into a 950 g stationary body . The loss in K.E. of the system will be

asked by Arashpardeep
  1. initial momentum = 0.050 *10 = .5

    final momentum = 1.00 * v = v

    so v = 0.5 m/s

    initial Ke = .5(.050)*100 = 2.5 Joules
    final Ke = .5(1.00)*.25 = .125 Joules

    posted by Damon
  2. Solutions

    posted by Ashok
  3. Solutions

    posted by Ashok
  4. Solutions

    posted by Ashok

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