Physical Chemistry

What is the mole fraction of alanine in 0.314m CH3CH(NH2)COOH(aq)?

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asked by Anonymous
  1. 0.314 m means 0.314 mol alanine in 1000g of water.
    moles = (1000g)/(18.02 g/mol H20) = 55.56 mol

    mole fraction (Xa) = moles of a/total moles
    mole fraction Alanine = (0.314)/(0.314+55.56)
    =2.41x10^-3

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    posted by Anonymous

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