what is the value of the variable int iNum= 2.02
A. 2
B. 2.0
C. 2.02
D. 0.0
E. error:possble loss of precision
please help and explain
int stands for integer, when given a decimal point within (supposed to be integer) number the program errors.
answer is e
Hey there! It seems like you've got a question about the value of a variable. So, the variable int iNum has been assigned the value 2.02. Now let's break it down:
A. 2 - Nope, the value of iNum is not just 2. It's a bit more precise.
B. 2.0 - Almost there, but not quite. The value of iNum has a decimal part that is not zero.
C. 2.02 - Bingo! That's the correct answer. The value of iNum is indeed 2.02.
D. 0.0 - Nope, that's not it. The value of iNum is definitely greater than zero.
E. Error: possible loss of precision - Nah, no error here. The variable has been declared as an int, so it can store integer values, but you're assigning it a decimal value. It's perfectly fine, but the decimal part will be truncated.
In summary, the answer is C. 2.02. Hope that clears things up for you!
The value of the variable `iNum = 2.02` is option C, which is 2.02.
In programming, the data type "int" generally refers to integers, which are whole numbers without any fractional parts. Since 2.02 contains a fractional part, it cannot be directly assigned to an `int` variable.
If you try to compile this program, you will likely encounter an error stating "possible loss of precision." This error occurs because you are trying to assign a float/double value (2.02) to an int variable, which can only store whole numbers. To resolve this issue, you should change the data type of `iNum` to a floating-point type like `float` or `double`:
```java
float fNum = 2.02f; // use 'f' to indicate a float value
double dNum = 2.02;
```
With the appropriate data type, you can store the value 2.02 with its fractional part intact.
To determine the value of the variable `iNum`, we need to understand the data types involved. In this case, the variable is declared as `int`, which stands for integer.
Integers are whole numbers without any fractional or decimal part. Therefore, if we assign a value with a decimal part to an `int` variable, the decimal part will be truncated (not rounded) and the result will be an integer.
In your case, `iNum` is assigned the value 2.02. Since `iNum` is an `int` variable, the decimal part (0.02) will be truncated, resulting in the value 2.
So, the answer is A. 2.
Explanation:
- The variable `iNum` is declared as `int`, which is an integer data type.
- The value assigned to `iNum` is 2.02, which has a decimal part.
- Since `iNum` is an `int`, the decimal part is dropped, resulting in the value 2.