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How fast (in rpm) must a centrifuge rotate if a particle 69-cm from the axis of rotation is to experience an acceleration of 200438 g's?

(can you show me how you get the answer) be thorough

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  1. a = 200438 g's
    =200438 * 9.81 m/s^2
    You have got to be kidding

    r = 0.69 meters

    a = omega^2 r
    solve for omega
    which is in radians/second
    divide by 2 pi to get revolutions per second
    multiply by 60 to get revolutions per minute

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    Damon

  2. centrifuge means centripetal force

    v^2 / r = 200438 g ... v in m/s

    rpm = v * 60 / (2 π r)

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    Scott

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