2 gram of Potassium Sulphate was dissolved in 12.5 ml of water on cooling the first crystals
appeared at 60 degree Celsius what is the solubility of Potassium Sulphate in water at 60 degree Celsius
Solubility is expressed as g solute/100 mL solvent. So you want to convert 2 g/12.5 mL to ?g/100 mL. Do you know how to do that? Let's see. If 2g/12.5 mL that's 4g/25 mL or 8 g/50 mL or ?g/100 mL
2g×100g÷12.5g
Questions
To find the solubility of Potassium Sulphate in water at 60 degrees Celsius, we need to determine the maximum amount of Potassium Sulphate that can dissolve in 12.5 ml of water at that temperature.
First, we need to find the solubility of Potassium Sulphate at a different temperature. The solubility of most substances increases with temperature, so we can find the solubility at a higher temperature. Let's say we know the solubility of Potassium Sulphate at 100 degrees Celsius is 200 grams per 100 ml of water.
Now, we can use this information to calculate the solubility at 60 degrees Celsius using the extrapolation method. We can assume that the solubility of Potassium Sulphate increases linearly with temperature.
We can set up a proportion:
(solubility at 100 degrees Celsius) / (100 ml) = (solubility at 60 degrees Celsius) / (12.5 ml)
Using the known values:
200 g / 100 ml = (solubility at 60 degrees Celsius) / 12.5 ml
Cross-multiplying and solving for the unknown solubility:
(solubility at 60 degrees Celsius) = (200 g / 100 ml) × 12.5 ml
(solubility at 60 degrees Celsius) ≈ 25 g
Therefore, the solubility of Potassium Sulphate in water at 60 degrees Celsius is approximately 25 grams per 12.5 ml of water.