Questions LLC
Login
or
Sign Up
Ask a New Question
Mathematics
Sequences
Divergence
Prove: If a sequence a_n diverges to infinity, then (a_N)^2 diverges to infinity as well.
1 answer
since a_n > 1, (a_n)^2 > a_n
You can
ask a new question
or
answer this question
.
Related Questions
1. What are the first 5 terms of the sequence given by the formula a_n= 6n + 1?
a. 7, 13, 19, 25, 31 b. 1, 7, 13, 19, 25 c. 6,
Determine if the sequence an*= {3/4, 1/8, -1/2, -9/8...} converges or diverges
then determine if the associated series 3/4 +1/8+
Sequences and Series Part 1
2. Write a recursive definition for the sequence 8, 6, 4, 2, … (1 point) a_1 = 8; a_n= a_(n–1)
1. Find all intervals on which the graph of y=(x^2+1)/x^2 is concave upward.
A. (negative infinity, infinity) B. (negative
what is the domain in interval notation when the restrictions are x cannot = 2 and x cannot = -2?
I got (-infinity, 2) U
determine if the series converges or diverges:
1/(ksqrt(k^2+1)) from k = 1 to infinity
Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.)
The divergence test applied to the series ∑n=1 to ∞ 3n/(8n+9) tells us that the series converges or diverges?
I got that it
If f(x)=x-7 and g(x)=sqrt(4-x), what is the domain of the function f/g?
a. (-infinity, 4) b. (-infinity, 4] c. (4, infinity) d.
i need help with problem d
Graph the arithmetic sequence an = –4, –1, 2, 5, 8, … a. What is the 8th term in the sequence?