physics science

a ball thrown vertically upward lands on the thrower's hand 24.5s. find (a) the time taken by the ball to reach its maximum height,(b) the maximum height attained by the ball, and (c) initial velocity of the ball

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  1. goes up for 24.5/2 seconds
    (by the way, no way! )

    v = Vi - 9.81 t
    v = 0 at top
    so
    Vi = -9.81(12.25)

    h = Vi t - 4.9 t^2
    h = Vi (12.5) - 4.9(12.5)^2

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  2. i dont no because i want a sulotion plz

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