Three point sized bodies each of mass M are fixed at three corners of light triangular frame of length L about an axis perpendicular to the plane of frame passing through centre of frame the moment of inertia of three bodies is
Ans : MLsquare

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  1. Oh come on, I already did two of these. Now all three masses are L/sqrt 3 from the axis

    3 M (L/sqrt3)^2 = 3 ML^2 /3 = M L^2

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  2. damon could u plss tell how all three masses are l /sqr 3

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