Chemistry

The radius of a magnesium atom is 160 pm & its mass is 4.04 X 10^-23 g. What is the density of the atom in grams per cubic centimeter?

Assume the atom is a sphere with:
Volume= (4/3)*pi*r^3

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  1. well I think it is 173 pm but oh well
    r = 160 * 10^-12 m * 10^2 cm/m
    = 160 *10^-10 cm = 1.6 *10^-9 cm

    vol = (4/3)pi (1.6)^3 * 10^-27 cm^3
    = 17.2*10^-27 cm^3

    so
    4.04*10^-23/(17.2 * 10^-27)
    = .235 * 10^4 g/cm^3
    = 2350 g/cm^3

    check my arithmetic !

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  2. well I think it is 173 pm but oh well
    r = 160 * 10^-12 m * 10^2 cm/m
    = 160 *10^-10 cm = 1.6 *10^-8 cm

    vol = (4/3)pi (1.6)^3 * 10^-24 cm^3
    = 17.2*10^-24 cm^3

    so
    4.04*10^-23/(17.2 * 10^-24)
    = .235 * 10^1 g/cm^3
    = 2.350 g/cm^3

    more reasonable

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  3. I did a double take for 2350. Hg, Au, U etc not even close to that.

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  4. I had a hunch it might not be quite that heavy :)

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