One number is twice the other.when the larger number is subtracted from 50.the result is two more than the smaller number subtracted from 40. Find the numbers
8 16
To solve this problem, let's assign variables to represent the numbers. Let's use "x" as the smaller number and "2x" as the larger number, as it is stated that one number is twice the other.
According to the information given, when the larger number (2x) is subtracted from 50, the result is two more than the smaller number (x) subtracted from 40. We can represent this as an equation:
50 - 2x = x - 40 + 2
Now, let's solve this equation to find the value of x.
First, simplify both sides of the equation by combining like terms:
50 - 2x = x - 38
Next, let's isolate the variable x by adding 2x to both sides of the equation:
50 - 2x + 2x = x - 38 + 2x
This simplifies to:
50 = 3x - 38
Now, let's isolate the variable x by adding 38 to both sides of the equation:
50 + 38 = 3x - 38 + 38
This simplifies to:
88 = 3x
Finally, divide both sides of the equation by 3 to solve for x:
88/3 = x
So, the value of x is approximately 29.33.
To find the larger number, substitute the value of x back into the equation. The larger number is 2x, so:
2 * (88/3) = 176/3
So, the larger number is approximately 58.67.
Therefore, the smaller number is approximately 29.33 and the larger number is approximately 58.67.