chemistry

Knowing that 1 mol of a certain monoprotico acid, HX, contained in 1 litre aqueous solution, this 50% ionized, point the value of its ionization constant.

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  1. (HX) = 1 mol/L = 1 M
    50% ionized means H^+ = 0.5M and X^- = 0.50
    ........HX ==>H^+ + X^-
    I......1.0....0.....0
    C......-0.5...0.5..0.5
    E.....0.5....0.5...0.5

    Plug the E line into the Ka expression and evaluate Ka.
    Post your work if you get stuck.

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