If f (x)= x^2-1 and f(2a)=35, then what could be the value of a ?
f(2a)=(2a)^2-1
So, now you just have to solve
4a^2-1=35
4a^2=36
a^2=9
a = ±3
To find the value of a, we need to substitute the given f(2a) value into the equation f(x) = x^2 - 1 and solve for a.
Given f(x) = x^2 - 1, we substitute x with 2a:
f(2a) = (2a)^2 - 1 = 4a^2 - 1
Since we know that f(2a) = 35, we can set up the equation:
4a^2 - 1 = 35
Now, let's solve the equation for a:
4a^2 - 1 = 35
4a^2 = 35 + 1
4a^2 = 36
a^2 = 36/4
a^2 = 9
Taking the square root of both sides, we get:
a = ± √9
Therefore, the two possible values for a could be a = 3 or a = -3.