physics

if a particle starting with certain initial velocity and uniform accelration covers a distance 12m in first 3 seconds and a distance of 30m in next 3 seconds.then find its inital velocity

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  1. (vi+v3)/2 = 12/3 = 4 and (v3+v6)/2 = 30/3=10
    so
    v3 =8-vi and v3 = 20-v6
    and
    v6=vi+6a
    so
    8-vi = 20 -vi -6a
    or
    6a = 12
    a = 2
    then
    vi + 3(2) = v3 and vi+v3 = 8
    so
    vi+6 = 8-vi
    2 vi = 2
    vi = 1

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  2. I am not so sure about the answer but I think :
    D1=12m ,T1=3secs ,D2=30m ,T2=3secs

    Initial velocity =
    V=d1/t1=12m/3secs=4m/s

    Please bear with me for I just showed my opinion, any mistake can be corrected .Thanks

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