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The relative molecular mass of calcium carbonate (CaCO3) is 100. What is the minimum volume of 2.0 M hydrochloric acid (HCl) that would be needed to completely react with 2.0 g of calcium carbonate?

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scienceguy

  1. CaCO3 + 2HCl > CaCl3 + CO2 + H2O

    2grams/100= .02 moles
    so you need .04 moles HCl

    molesHCl=volume*Molarity
    volume = .04/2= .02 liters or 20 ml

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    bobpursley

  2. Thanks! Bob

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    ddval

  4. Wow love u all

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    Anonymous

  5. Thanks alot

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    Anonymous

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