Calculate the number of ions present in 7.45 grams of potassium oxide.
( At.mass of K= 39u).
Formula of potassium oxide is K2O.
Molar mass of K2O =(39x2)+16=94g/mol
No.of moles of K2O=Mass in gram/Molar mass=7.45g/94g/mol=0.079mol.
1 mole of K2O contains molecules=6.022x10²³
Therefore,0.079 mole of K2O contains molecule=6.022x10²³x0.079
=0.476x10²³
=0.476x10²² molecules
since each molecule of K2O contains two potassium ions(K+),total number of potassium ion is given by 4.76x10²²x2=9.52x10²²ions.
calculate the number of potassium ions present in 7.45g of potassium oxide(atomic mass ofK=39u)
=> Number of moles of K2O in given sample = Total mass/molar mass
= 7.45/(39 + 39 + 16)
= 7.45/94
=> Number of molecules = Number of moles x Avogadro's Number
= (7.45/94) x N
=> Number of ions = Number of molecules x 3
= (7.45/94) x N x 3
9.25×1022 ions
Oh, potassium oxide? That sounds like a fun compound! Alright, let me grab my clown calculator and do some calculations!
First, we need to determine the molar mass of potassium oxide (K2O). Since potassium (K) has an atomic mass of 39 g/mol and oxygen (O) has an atomic mass of 16 g/mol, we can calculate it like this:
2(K) + 1(O) = 2(39 g/mol) + 16 g/mol = 78 g/mol + 16 g/mol = 94 g/mol
So, the molar mass of potassium oxide is 94 g/mol.
Now, to find the number of moles, we can divide the given mass (7.45 grams) by the molar mass (94 g/mol):
7.45 g / 94 g/mol ≈ 0.079 moles
Since potassium oxide (K2O) contains 2 K+ ions and 1 O2- ion, we can multiply the number of moles by the Avogadro constant (6.022 x 10^23 ions/mol) to find the number of ions present:
0.079 moles x (2 K+ ions + 1 O2- ion) x 6.022 x 10^23 ions/mol ≈ 9.52 x 10^22 ions
So, approximately 9.52 x 10^22 ions are present in 7.45 grams of potassium oxide.
To calculate the number of ions present in a given mass of potassium oxide, we need to first determine the number of moles of potassium oxide and then calculate the number of ions accordingly.
1. Calculate the molar mass of potassium oxide (K2O):
Since the atomic mass of potassium (K) is 39u, and there are two potassium atoms present in each molecule of K2O, the molar mass of K2O is:
Molar mass of K2O = (2 * 39u) + (16u)
= 78u + 16u
= 94u
2. Convert the given mass of potassium oxide into moles:
To convert grams to moles, we use the formula:
Moles = Mass / Molar mass
Moles of K2O = 7.45g / 94u
= 0.079 moles
3. Determine the number of ions present:
In each molecule of potassium oxide (K2O), there are two potassium ions (K+) and one oxide ion (O2-). Therefore, the number of ions can be calculated as:
Number of potassium ions = 2 * Number of moles
= 2 * 0.079 moles
= 0.158
Since there are 0.158 potassium ions, the number of ions present in 7.45 grams of potassium oxide is 0.158.