CONSTRUCT ON A SINGLE DIAGRAM ,TRIANGLE ABC IN WHICH BC=10CM,CA=7CM, AB= 8,5CM ,THE LOCUS POINT P GIVEN THATBP==PC,THE LOCUS OF A POINT Q SUCH THAT AQ=4CM
First, please do not use all capitals. Online it is like SHOUTING. Not only is it rude, but it is harder to understand. Thank you.
Second, we cannot diagram on these posts.
If BP=PC, then P is on the perpendicular bisector of BC.
As for Q, I have no idea where M is...
Sorry. I got confused by the SHOUTING.
If AQ is a constant distance, then Q lies on a circle centered at A.
draw a line with bc 10cm that the base you should label the point
then measure with a compass 7cm then place it on c
then cut an arc or mark it up
then measure 8.5cm with aruler then then do the same thing u did for c . place and mark
To construct the diagram, follow these steps:
1. Draw a line segment AB of length 8.5 cm using a ruler.
2. At point A, draw a line segment AC of length 7 cm that forms an angle with AB.
3. At point B, draw a line segment BC of length 10 cm that forms an angle with AB.
4. Use a compass to draw a circle centered at point B with a radius of 5 cm. This circle represents the locus of points equidistant from points B and C.
5. Mark the intersection of this circle and line segment BC as point P. This point satisfies the condition BP = PC.
6. Use a compass to draw a circle centered at point A with a radius of 4 cm. This circle represents the locus of points that are 4 cm away from point A.
7. Mark the intersection of this circle and line segment AB as point Q. This point satisfies the condition AQ = 4 cm.
8. Finally, connect points B and C to form the triangle ABC.
Your completed diagram should now have triangle ABC with sides BC = 10 cm, CA = 7 cm, and AB = 8.5 cm. Point P should be the intersection of the circle centered at B with a radius of 5 cm and line segment BC. Point Q should be the intersection of the circle centered at A with a radius of 4 cm and line segment AB.