A body is thrown up with the velocity of 20 metre per second . It s uniformly at the rate of 10 metre per second square. Find the velocity after 2 seconds?
v(t) = 20-10t
Think on it. Each second, the velocity decreases by 10 m/s
To find the velocity of the body after 2 seconds, we can use the equation of motion for uniformly retarded motion:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Given:
u = 20 m/s
a = -10 m/s^2 (negative sign indicates retardation)
t = 2 s
Substituting the given values into the equation, we have:
v = 20 m/s + (-10 m/s^2) * 2 s
v = 20 m/s - 20 m/s
v = 0 m/s
Therefore, the velocity of the body after 2 seconds is 0 m/s.