I NEED HELP PLEASE!!!!!!!!!
A rectangular table is five times as long as it is wide. If the area is 50 ft.^2, find the length and the width of the table.
The width of the table is______ ft.
The lenght of the table is ______ ft.
x
5x
To solve this problem, we can set up two equations based on the given information:
1) The rectangular table is five times as long as it is wide.
2) The area of the table is 50 square feet.
Let's call the width of the table "w" and the length of the table "l".
Based on the first equation, we know that the length is five times the width, so we can express this as:
l = 5w
To find the area of a rectangle, we multiply the length by the width. So according to the second equation:
lw = 50
Now, we can substitute the first equation into the second equation to solve for the width:
(5w)(w) = 50
5w^2 = 50
Divide both sides of the equation by 5:
w^2 = 10
Take the square root of both sides to solve for w:
w = √10
This gives us the width of the table, but we need to find the length as well. We can substitute the value of w back into the first equation to solve for l:
l = 5(√10)
Therefore, the width of the table is √10 feet, and the length of the table is 5√10 feet.