# physics

Two books are stacked on top of each other. Book 1 is on top of Book 2. Book 1 has a string attached to it. The string is connected to the wall. The wall is to the left of the stacked Books. Book 2 is pulled to the right with a force F big enough to move Book 2. All surfaces have the same coefficient of friction value.

What is the tension on the string that's attached to Book 1?

Find the acceleration of Book2

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1. Riley & Monica, there is no need to change pen names. Most of the time students do that to hide the number of posts they make on the same subject, which is not necessary, because we know. Using the same name reduces repetition, like references, explanations of certain terms, definitions, etc.

Draw a free-body-diagram (FBD) for book2.
You should have the weight (N1) of book1 one acting on the top face, and the combined weight of the two (N2) on the bottom surface. If book2 is in motion, then the total frictional force resisting motion is
μk(N1+N2).
Since it is in motion, we know that
F≥μk(N1+N2).
The difference is what will enable book2 to accelerate, according to Newton's second law, F=ma, thus
a=F/m=net force on book2/m2
where m2=mass of book2 (the moving object)
net force on book2
=F - μk(N1+N2)

All formulas and equations work when using consistent units.

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