# Math (Calc) (Differential Equation Solution)

Some of the curves corresponding to different values of C in the general solution of the differential equation are shown in the graph. Find the particular solution that passes through the point (0, 2).

y(x^2+y) = C

2xy + (x^2+2y)y' = 0

How would I start this problem to solve for the solution? Thanks in advance!

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1. huh? what's to start?

The 1st equation is the solution to the second. All you have to do is find C such that

y(x^2+y) = C

goes through (0,2).

2(0+2) = C

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