Chem

A bottle of win contains 12.5% ethanol by volume. The density of ethanol (C2H5OH) is .79 g/mL. Calculate the concentration of ethanol in wine as mass percent and molality.

I calculated molality as 2.4 m/kg, but I'm stumped on the mass percent [although I'm hitting the right area.] Is the solvent water?

I calculated the molality as 2.45 mols/kg solvent so I assume you are doing that part correctly.

For percent by mass.
12.5 v/v percent is
12.5 mL EtOH in (12.5 mL EtOH + 87.5 mL H2O).
12.5 mL with density of 0.79 g/mL = 9.875 g.
mass %= [mass EtOH/(mass EtOH + mass H2O)]x 100 =
[9.875g/(9.875 g + 87.5 g)]x100 = 10.14 w/w percent.
Check my thinking. Check my arithmetic.

asked by Jessica
  1. It comes out to be 10.2. Check your math and do it over again. Your very close to the answer

    posted by Evelyn L

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