physics

An object is launched at an angle of 78º above the horizontal with an initial speed of 120 m/s. Find (a) the maximum altitude reached by the object, (b) its total time of flight, and (c) its horizontal range

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  1. V1= 120m/s[78o].
    X1 = 120*Cos78 = 24.9 m/s.
    Y1 = 120*sin78 = 117.4 m/s.

    a. Y2^2 = Y1^2 + 2G*h.
    0 = 117.4^2 - 19.6h, h = ?.

    b. V2 = V1 + g*Tr.
    0 = 117.4 - 9.8Tr, Tr = 12 s. = Rise time.

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    posted by Henry
  2. h = 0.5g*Tf^2 = 703 m.
    4.9Tf^2 = 703, Tf = Fall time = ?.

    Tr+Tf = Time in light.

    c. Range = X1*(Tr+Tf).

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    posted by Henry

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