Math (Double checking trig identity)
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Intergrate ¡ì sec^3(x) dx could anybody please check this answer. are the steps correct? thanks. = ¡ì sec x d tan x = sec x tan x  ¡ì tan x d sec x = sec x tan x  ¡ì sec x tan^2(x) dx = sec x tan x + ¡ì sec x dx  ¡ì
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So I am suppose to evaulate this problem y=tan^4(2x) and I am confused. my friend did this : 3 tan ^4 (2x) d sec^ 2x (2x)= 6 tan ^4 (2x) d sec^2 (2x) She says it's right but what confuses me is she deriving the 4 and made it a
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could anybody please explain how sec x tan x  ¡ì sec x tan^2(x) dx = sec x tan x + ¡ì sec x dx  ¡ì sec^3(x) dx What I don't understand about your question is what is ¡ì ? i just want to know if those two equations are
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1.) which of the following represents dy/dx when y=e^2x Sec(3x)? A.3e^2x sec(3x) tan (3x)2e^2x Sec(3x)
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Calculus PLEASE check my work ,
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asked by anon on March 12, 2011