A constant force acts on a body mass 0.9 kg at rest for 10s.If the body moves a distance of 250m ,the magnitude of the force is
Ooops. My bad. It should have been
55.5F = 250
F = 4.5N
To find the magnitude of the force, we can use Newton's second law of motion, which states that force (F) is equal to the mass (m) of an object multiplied by its acceleration (a).
To find the acceleration, we can use the equation of motion: distance (d) = initial velocity (u) * time (t) + 0.5 * acceleration (a) * time squared (t^2).
Given:
Mass (m) = 0.9 kg
Time (t) = 10 s
Distance (d) = 250 m
We need to find the acceleration first:
Since the body is at rest initially, its initial velocity (u) is 0 m/s.
Using the equation of motion: d = ut + 0.5at^2.
250 = 0 * 10 + 0.5 * a * (10^2).
250 = 0.5 * 100a.
250 = 50a.
a = 250 / 50.
a = 5 m/s^2.
Now that we know the acceleration, we can find the magnitude of the force using Newton's second law of motion:
F = m * a.
F = 0.9 kg * 5 m/s^2.
F = 4.5 N.
Therefore, the magnitude of the force acting on the body is 4.5 Newtons.
F = ma, so a = F/m
s = 1/2 at^2 = 1/2 (F/m) t^2
so,
1/2 (F/0.9)*10^2 = 250
F = 55.5 N