What is a factor of: 104x^3-52x^8?
I can't figure out the process of this problem.
Note that both terms have x to a power (3 and 8), and that 104 is divisible by 52. So factor out 52 and x to the lowest power (3).
52 x^3 * (2 - x^5)
so if i factor it out i would get 2x^3-1x^8?
You don't have to put "1" in front of the x^8. You did not factor out the common factor of x^3.
I already gave you the factored answer.
To find the factors of the expression 104x^3 - 52x^8, we can start by factoring out the greatest common factor (GCF) of the terms. In this case, the GCF is 4x^3 because 4 is the greatest common factor of 104 and 52, and x^3 is the highest power of x that appears in both terms.
Step 1: Factor out 4x^3 from both terms:
4x^3(26 - 13x^5)
Now we can see that the expression 26 - 13x^5 is a binomial, which can be factored further.
Step 2: Factor out the GCF from 26 and -13x^5, which is 13:
4x^3(13(2 - x^5))
Now we have factored out the GCF from both terms and the expression is fully factored as 4x^3(13)(2 - x^5).
The factors of 104x^3 - 52x^8 are: 4x^3, 13, and (2 - x^5).