# Chemistry

What volume of 0.200 M K2C2O4 is required to completely react with 30.0 mL of 0.100 M Fe(NO3)3?

2Fe(NO3)3 + 3K2C2O4 --> Fe2(C2O4)3 + 6KNO3

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1. mols Fe(NO3)3 = M x L = ?
Use the coefficients in the balanced equation to convert mols Fe(NO3)3 to mols K2C2O4.
Then M K2C2O4 = mols K2C2O4/L K2C2O4. You know mols and M, solve for L and convert to mL if needed. Post your work if you get stuck.

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