Use the atomic weight of carbon and chlorine to determine the theoretical value of the molecular weight of CH3OH Or methanol.( atomic weights (c=12, cl=35.5).
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Where does the Chlorine come in?
CH3OH = 12 + 3*1 + 16 + 1 = 32
regarding the same question above, will the formula (m=n*mr) be used?
If so, what values will we be substituting in n and mr?
To determine the theoretical value of the molecular weight of CH3OH (methanol), we need to add up the atomic weights of all the atoms in the molecule.
The molecular formula of methanol, CH3OH, tells us that there is one atom of carbon (C), four atoms of hydrogen (H), and one atom of oxygen (O).
Given that the atomic weight of carbon is 12 and the atomic weight of oxygen is 16, we can use these values to calculate the molecular weight of CH3OH.
Molecular weight = (Atomic weight of C) + (Atomic weight of H) x 3 + (Atomic weight of O) + Atomic weight of H
Substituting the values:
Molecular weight = (12) + (1 x 3) + (16) + (1)
Molecular weight = 12 + 3 + 16 + 1
Molecular weight = 32
Therefore, the theoretical molecular weight of CH3OH (methanol) is 32.