The table shows the snack preferences of 50 shoppers at the mall. What is the probability that one shopper, selected at random from the 50 surveyed, preferred the
potato chips or pretzels?
------------------------------------
| Food | Number of Shoppers |
|Fruit snacks| 9 |
|Potato chips| 12 |
| Apple | 3 |
| Pretzels | 14 |
| Water | 12 |
------------------------------------
A. 1/5
B. 13/25
C. 1/10
D. 18/25
Its been years!!! Still no answers...sad
It means the test ended before I could think properly, it was a 10 minute test and I had about 3 minutes left when I attempted to post this I wasted 30 seconds posting, got a drink and came back. I tried to explain why I thought it was the correct answer but by the time I was explaining the test finished; which is fine. Overall thanks Ms. Sue for trying to help.
SO WHAT THE ANSWER?!?!?!
The answer is 1/5
Sorry; it was a timed test so I had to go with it but thanks for trying to help Ms. Sue! Your awesome.
SSOO WWHHAATT IISS TTHHEE AANNSSWWEERRSS?
Yeah
someone please put all the test answers
I feel as if it's c any help would be nice.
sooo whats the answer
B R U H -.-
1/5
anon is wrong its 13/25
thx
So should I just give up on the answers
i have to finish this today people!
The answer is yvng96 my ig go add me
The answer is 13/25s i took the test and got the question wrong bc of you people -Your local cheez it
The table shows the snack preferences of 50 shoppers at the mall. What is the probability that one shopper, selected at random from the 50 surveyed, preferred the
potato chips or pretzels?
------------------------------------
| Food | Number of Shoppers |
|Fruit snacks| 9 |
|Potato chips| 12 |
| Apple | 3 |
| Pretzels | 14 |
| Water | 12 |
------------------------------------
A. 1/5
B. 13/25
C. 1/10
D. 18/25
The probability that one shopper, selected at random from the 50 surveyed, preferred the potato chips or pretzels is:
(Number of shoppers who preferred potato chips + Number of shoppers who preferred pretzels) / Total number of shoppers
= (12 + 14) / 50
= 26/50
= 13/25
Answer: B. 13/25
A number cube is rolled 360 times, and the results are recorded as follows :96 ones 31 twos, 49 threes, 76 fours, 45 fives, and 63 sixes. What is the experimental probability of rolling a 2 or a 3?
The number of times a 2 or a 3 is rolled is:
31 (number of twos) + 49 (number of threes) = 80
The total number of rolls is:
96 + 31 + 49 + 76 + 45 + 63 = 360
The experimental probability of rolling a 2 or a 3 is:
80 / 360 = 4/18 = 2/9
Answer: 2/9
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Marissa is researching information about martial arts students. She found that 7 out of 12 martial artists practice every day. There are 144 martial arts students at a school.
a. Predict how many students practice every day.
b. What is the sample size?
a. To predict how many students practice every day, we can set up a proportion:
7/12 = x/144
where x is the number of students who practice every day.
To solve for x, we can cross-multiply:
12x = 7 * 144
x = (7 * 144) / 12
x = 84
So, we predict that 84 students practice every day.
b. The sample size is 144, as stated in the problem.
bot can you talk rq
Yes, I can communicate through text. How can I assist you?
The table shows the drink preferences of 50 shoppers at the mall. What is the probability that one shopper, selected at random from the 50 surveyed, preferred either Drink A or Drink B?
Without the table to show the drink preferences, it is not possible to calculate the probability of a shopper preferring either Drink A or Drink B. Please provide the table or the necessary information to solve the problem.
Drink: A, Number of Shoppers: 7
Drink: B, Number of Shoppers: 8
Drink: C, Number of Shoppers: 10
Drink: D, Number of Shoppers: 11
Drink: E, Number of Shoppers: 14
The probability that one shopper, selected at random from the 50 surveyed, preferred either Drink A or Drink B is:
(Number of shoppers who preferred Drink A + Number of shoppers who preferred Drink B) / Total number of shoppers
= (7 + 8) / 50
= 15/50
= 3/10
So, the probability is 3/10 that one shopper, selected at random from the 50 surveyed, preferred either Drink A or Drink B.
Hey bot can u speak
As an AI language model, I cannot speak, but I can communicate through text. How can I assist you today?
The table shows the snack preferences of 50 shoppers at the mall. What is the probability that one shopper, selected at random from the 50 surveyed, preferred the
potato chips or pretzels?
------------------------------------
| Food | Number of Shoppers |
|Fruit snacks| 9 |
|Potato chips| 12 |
| Apple | 3 |
| Pretzels | 14 |
| Water | 12 |
------------------------------------
A. 1/5
B. 13/25
C. 1/10
D. 18/25
The probability that one shopper, selected at random from the 50 surveyed, preferred the potato chips or pretzels is:
(Number of shoppers who preferred potato chips + Number of shoppers who preferred pretzels) / Total number of shoppers
= (12 + 14) / 50
= 26/50
= 13/25
Therefore, the answer is B. 13/25.
a standard number cube with numbers 1 through 6 is rolled. what is the probability of rolling a number greater than 5?
The number of possible outcomes when rolling a standard number cube is 6 (numbers 1 to 6).
Out of those 6 possible outcomes, there is only one number greater than 5.
So, the probability of rolling a number greater than 5 is:
1/6
Answer: 1/6
A number cube is rolled 360 times, and the results are recorded as follows :61 ones 26 twos, 36 threes, 76 fours, 73 fives, and 88 sixes. What is the experimental probability of rolling a 2 or a 3?
The number of times a 2 or a 3 is rolled is:
26 (number of twos) + 36 (number of threes) = 62
The total number of rolls is:
61 + 26 + 36 + 76 + 73 + 88 = 360
The experimental probability of rolling a 2 or a 3 is:
62 / 360 = 31/180
Answer: 31/180
from a barrel of colored marbles, you randomly select 5 blue, 2 yellow, 3 red, 4 green, and 2 purple marbles. find the experimental probability of randomly selecting a marble that is not yellow
The total number of marbles is:
5 (blue) + 2 (yellow) + 3 (red) + 4 (green) + 2 (purple) = 16
The number of marbles that are not yellow is:
16 - 2 (yellow) = 14
The experimental probability of randomly selecting a marble that is not yellow is:
14 / 16 = 7/8
Answer: 7/8
the probability of winning a game is 25%, how many times should you expect to win if you play 40 times
To find the number of times you should expect to win if you play 40 times, we can use the formula:
Expected value = Probability of winning * Number of times played
Here, the probability of winning is 25% or 0.25, and the number of times played is 40. So, the expected value is:
Expected value = 0.25 * 40 = 10
Therefore, you should expect to win 10 times if you play the game 40 times.
a survey showed that 62% of car owners prefer two-door cars, 26% prefer four-door cars, and 12% have no preference. you ask 400 people. how many do you think will prefer the two-door cars?
Out of the 400 people, the expected number of people who prefer two-door cars is:
Expected number = Probability of preferring two-door cars * Total number of people
= 0.62 * 400
= 248
Therefore, you can expect that 248 people out of 400 will prefer two-door cars.
mary works in a factory that produces 1,000 telephones each day. when 30 telephones were sampled, it was found that 9 were defective. estimate how many telephones are defective each day
To estimate the number of defective telephones produced each day, we can use proportions.
If 9 out of 30 telephones were defective, then the proportion of defective telephones in the sample is:
9 / 30 = 0.3
We can use this proportion to estimate the number of defective telephones produced each day:
Number of defective telephones = Proportion of defective telephones * Total number of telephones produced
= 0.3 * 1,000
= 300
Therefore, an estimate of 300 telephones are defective each day.
the spinner is divided into three equal parts. use a tree diagram to find that the spinner will land on a consonant both times if the spinner is spun twice
A circle is divided equally into three sections labeled N, E, and U.
Here is the tree diagram to find the probability of landing on a consonant both times if the spinner is spun twice:
-------N
|
|-------E
|
|-------U
|
Start- - |
|
|-------N
|
|-------E
|
|-------U
There are 3 possible outcomes for the first spin: N, E, or U. For each of these outcomes, there are 2 possible outcomes for the second spin: a consonant or a vowel. We want to find the probability of getting a consonant on both spins, given that the first spin resulted in a consonant.
- If the first spin is N, the second spin can result in a consonant (N) or a vowel (E or U)
- If the first spin is E, the second spin can result in a consonant (E) or a vowel (N or U)
- If the first spin is U, the second spin can result in a consonant (U) or a vowel (N or E)
Out of those 6 outcomes, only 3 result in getting a consonant both times: NN, EE, and UU. So, the probability of getting a consonant both times is 3/9, or 1/3.
Answer: 1/3
a yogurt shop offers 5 different flavors of frozen yogurt and 11 different toppings. how many choices are possible for a single serving of frozen yogurt with one topping?
To find the total choices possible for a single serving of frozen yogurt with one topping, we can use the multiplication principle of counting, which states that if there are m ways to do one thing and n ways to do another, then there are m x n ways to do both things.
Here, there are 5 different flavors of frozen yogurt and 11 different toppings. Therefore, the total choices possible for a single serving of frozen yogurt with one topping are:
5 (flavors) x 11 (toppings) = 55
Thus, there are 55 choices possible for a single serving of frozen yogurt with one topping.
suzy likes to mix and match her 3 necklaces, 2 bracelets, and 6 hats. the colors are listed in the table. on monday, she randomly picks a bracelet, a necklace, and a hat. what is the probability of suzy choosing a red bracelet and silver hat?
------------------------------------
| Necklace | Bracelet | Hat
| red | red | silver
| green | black | yellow
| gold | (blank) | green
| (blank) | (blank) | gold
| (blank) | (blank) | black
| (blank) | (blank) | white
------------------------------------
Out of the 2 bracelets, only one is red, and out of the 6 hats, only one is silver. Therefore, the probability of choosing a red bracelet and a silver hat is:
(1/2) * (1/6) = 1/12
Thus, there is a 1/12 probability of Suzy choosing a red bracelet and a silver hat when she randomly picks one bracelet, one necklace, and one hat.
which events are not independent?
A. you draw two colored marbles without replacement and get one red and one blue
B. you pull a green tile from a bag of tiles, return it, then pull a yellow tile
C. you toss two coins and get one head, one tail.
D. you choose two different ice cream flavors for a cone
A. You draw two colored marbles without replacement and get one red and one blue: The events in this scenario are not independent because the outcome of the first draw affects the probability of the outcome of the second draw.
B. You pull a green tile from a bag of tiles, return it, then pull a yellow tile: The events in this scenario are independent because the first tile is returned to the bag, so the probability of pulling a yellow tile is not affected by the first draw.
C. You toss two coins and get one head, one tail: The events in this scenario are not independent because the outcome of the first toss affects the probability of the outcome of the second toss.
D. You choose two different ice cream flavors for a cone: The events in this scenario are independent because the first flavor is chosen, and it does not affect the probability of choosing the second flavor.
Therefore, events A and C are not independent.
you have to choose one
The answer is A. You draw two colored marbles without replacement and get one red and one blue.
a coin is tossed and a number cube is rolled. what is the probability that the coin shows heads and the number cube rolls 5?
The probability of getting heads on a coin is 1/2, and the probability of rolling a 5 on a number cube is 1/6.
To find the probability of both events occurring (coin shows heads and the number cube rolls 5), we can use the multiplication rule of probability, which states that the probability of two independent events occurring together is the product of their individual probabilities. Therefore, the probability of getting heads on a coin and rolling a 5 on a number cube is:
(1/2) * (1/6) = 1/12
So the probability of the coin showing heads and the number cube rolling 5 is 1/12.
A single, standard number cube is tossed. What is the probability of getting a 4 or 5?
A. 1
B. one-fifth
C. one-third
D. start fraction 1 over 6 end fraction
The standard number cube has 6 equally likely outcomes, i.e., 1, 2, 3, 4, 5, and 6.
The favorable outcomes are 4 and 5, i.e., 2 of the 6 outcomes.
Therefore, the probability of getting a 4 or 5 on a single, standard number cube is:
Favorable outcomes / Total outcomes
= 2 / 6
= 1/3
Hence, the answer is C. One-third.
A standard number cube with the numbers 1 through 6 is rolled. Find the probability of rolling a number greater than 4.
A. start fraction 1 over 6 end fraction
B. start fraction 1 over 3 end fraction
C. start fraction 5 over 6 end fraction
D. start fraction 2 over 3 end fraction
The total possible outcomes when rolling a standard number cube is 6 (numbers 1 to 6).
The numbers that are greater than 4 are 5 and 6.
Therefore, the probability of rolling a number greater than 4 is:
Number of outcomes that are greater than 4 / Total number of possible outcomes
= 2/6
= 1/3
So the answer is B. start fraction 1 over 3 end fraction.
A number cube is rolled 360 times, and the results are recorded as follows: 61 ones, 26 twos, 36 threes, 76 fours, 73 fives, and 88 sixes. What is the experimental probability of rolling a 2 or a 3?
A. 0.07
B. 0.17
C. 0.26
D. 0.83
Why do you think it's 1/10?
yes plz I need help or I will get in trouble if I fell this
Thanks for the explanation.
You're welcome.