how do I solve this?
0.02e^-0.244t=0.06
I know I divide by the constant to get :
e^-0.244t=3
but I'm not sure what to do after. do I take ln of both sides?
Yes. logs and exponents are inverse operations; one undoes the other:
e^(-0.244t) = 3
-0.244t = ln3
t = ln3/-0.244 = -4.5