A chemist prepares a 45.0-g sample of carbon tetrachloride (CCl4). How many moles of this compound has she prepared? (Note: The atomic weight of carbon is 12.0 and of chlorine is 35.5.) how do i do this?
1 mole of carbon tetrachloride is 154 grams. Divide the sample by the molar mass to get the number of moles. It should be about 0.292 moles
To find out how many moles of carbon tetrachloride (CCl4) you have prepared, you will need to use the given mass and molar masses of carbon and chlorine.
First, determine the molar mass of CCl4 by adding up the molar masses of carbon (C) and chlorine (Cl).
Molar mass of CCl4 = (Molar mass of C) + 4 x (Molar mass of Cl)
The molar mass of carbon (C) is 12.0 g/mol, as given in the question. The molar mass of chlorine (Cl) is 35.5 g/mol.
Molar mass of CCl4 = 12.0 + 4 x 35.5 = 12.0 + 142.0 = 154.0 g/mol.
Now that you know the molar mass of CCl4, you can use this value to calculate the number of moles using the formula:
Number of moles = Mass of compound / Molar mass
Substituting the given mass of 45.0 g into the formula, you can calculate the number of moles:
Number of moles = 45.0 g / 154.0 g/mol
Calculating this expression results in:
Number of moles = 0.292 mole (rounded to three decimal places).
Therefore, the chemist has prepared approximately 0.292 moles of carbon tetrachloride (CCl4).