A transformer has 120 V across the 100-turn primary coil and has 5 turns in the secondary coil. If the current in the primary coil is 0.1 A, how much power is dissipated in the secondary coil?
To find the power dissipated in the secondary coil of a transformer, we need to use the formula P = VI, where P is power, V is voltage, and I is current.
1. First, let's find the voltage across the secondary coil. In a transformer, the ratio of turns in the primary coil to turns in the secondary coil is equal to the ratio of voltage in the primary coil to voltage in the secondary coil.
- Given that the primary coil has 100 turns and the voltage across it is 120 V, and the secondary coil has 5 turns, we have:
100/5 = 120/V_secondary
- Solving for the voltage across the secondary coil:
V_secondary = (120 V) * (5 turns / 100 turns)
V_secondary = 6 V
2. Now that we have the voltage across the secondary coil, we can calculate the power dissipated.
- The current in the primary coil is 0.1 A, and the voltage across the secondary coil is 6 V.
- Using the formula P = VI, we have:
P = (0.1 A) * (6 V)
P = 0.6 W
Therefore, the power dissipated in the secondary coil of the transformer is 0.6 Watts.