A proton accelerates through a particle accelerator, with a final speed of 8.0 x 10^6 m/s. It experiences a magnetic field of 3.0T that is produced by steering magnets inside the accelerator. What is the number of the magnetic force pulling on the proton?
To determine the magnetic force pulling on a proton, we can use the formula:
F = qvB
Where:
F is the magnetic force,
q is the charge of the particle,
v is the velocity of the particle, and
B is the magnetic field strength.
In this case, we are given:
v = 8.0 x 10^6 m/s (velocity of the proton),
B = 3.0 T (magnetic field strength), and
q = charge of a proton = +1.6 x 10^-19 C.
Now, we can substitute the given values into the formula to calculate the magnetic force:
F = (1.6 x 10^-19 C) * (8.0 x 10^6 m/s) * (3.0 T)
= 3.84 x 10^-12 N
Therefore, the magnitude of the magnetic force pulling on the proton is approximately 3.84 x 10^-12 N.