If cos of theta= -7/12 and theta is in quadrant 2 then find
a. tan(theta) cot (theta)=
b. csc(theta) tan(theta)=
c. sin^2(theta)+ cos^2(theta)=

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asked by Bob
  1. cosθ = x/r, so

    x = -7
    r = 12
    y = √95

    Now, recall that
    sinθ = y/r
    tanθ = y/x

    and let 'er rip.

    (a) and (c) should require no calculation at all...

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    posted by Steve

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