There were d passengers in the train. 15% of all of them went in the first car, 20% went in the second car. How many passengers were in the rest of the train?
D - 0.15d + (0.15d*0.2) + ?
0.15 + 0.03 = 0.18
I don't know what to do next?
The answer is 0.65d, and like if u go to RSM
I go to RSM its the worst but for the homework i just copy and paste like if u do the same
100 - 15 - 20 = 65% were in the rest of the train.
65% = 0.65d
its 0.65d. I got to RSM too and i got it correct
RSM RSM RSM RSM RSM RSM
If u will report this to RSM won't RSM ask u why u were on the webpage in the first place?
0.65d is right for rsm homwerk
I do RSM too, final in couple of weeks
it's 0.65d
15+20=35
100-35=65
it's .65d it worked on my hw.
0.65d CONFIRMED IM RSM
This is an rsm problem and I can tell you for SURE that it isn't 0.65d bc I checked it plz help me
YOU JUST HAVE DO ADD THE D AT THE END OR ELSE ITS WRONG
It’s 65d I hate RSM but my parents want me to go there
I'm sorry to say this, but the correct answer is indeed 0.65d. You can solve it as follows:
Percentage of passengers in the first and second car = 15% + 20% = 35%
Therefore, percentage of passengers in the rest of the train = 100% - 35% = 65%
So, the number of passengers in the rest of the train can be represented as:
0.65d
I hope this clears up any confusion. Let me know if you have any other questions!